IOR Reference

pixie · Post by **pixie** » Tue Feb 12, 2008 10:34 am

http://www.ps.missouri.edu/rickspage/re ... ction.html

This got to be the most complete reference I'd found on the subject as it covers not only transparent mediums...

I hope it is of some use, to you and to the Indigo Knowledge Base

psor · Post by **psor** » Tue Feb 12, 2008 10:38 am

Thanx mate! Good resource unfortunately I've got the feeling that it
will be gone in a few days. So it would be very kind if someone with
Wiki experience could copy/paste this into the Indigo Wiki.

take care
psor

dougal2 · Post by **dougal2** » Tue Feb 12, 2008 10:54 am

huh? it's been there since 1998 psor.

edit: f***ing hell, that's a decade ago!

psor · Post by **psor** » Tue Feb 12, 2008 11:04 am

*LOOOL*

There's a misunderstanding Doug! I meant the link on this forum,
or better the thread will be buried in a few days and for new guys
it is easier to find stuff like that in the Wiki or in a sticky thread.

Hope this clears up my statement ...

take care
Oleg

dougal2 · Post by **dougal2** » Tue Feb 12, 2008 11:05 am

oh, I see what you mean. I'll put a link in the Wiki somewhere.

edit: done.
http://www.indigorenderer.com/joomla/in ... 9&id=links

psor · Post by **psor** » Tue Feb 12, 2008 11:10 am

Thanx!

pixie · Post by **pixie** » Wed Feb 13, 2008 5:31 am

http://en.wikipedia.org/wiki/Glass

Also has a nice set of IOR, and also dispersion. How do one convert this values to Indigo?

Kram1032 · Post by **Kram1032** » Wed Feb 13, 2008 5:55 am

Directly, I guess..

10^4×(nF-nC) ->
You need to multiply the dispersion by 0.0001

But what do we have the huge schott library for?

[EDIT] [CORRECTED]

pixie · Post by **pixie** » Wed Feb 13, 2008 8:10 am

There's more life to it then glass...

Kram1032 · Post by **Kram1032** » Wed Feb 13, 2008 8:12 am

yeah, true^^
Though, it's not that accurate. Would be cool to have all those as tabulated spectral materials

pixie · Post by **pixie** » Thu Feb 14, 2008 1:28 pm

I see Why I couldn't get the result right, I was multiplying by 0.0001 instead of 0000.1...

Kram1032 · Post by **Kram1032** » Fri Feb 15, 2008 12:19 am

0.1? Doesn't make sense, when it's 10^4 ....

pixie · Post by **pixie** » Fri Feb 15, 2008 2:30 am

You need to multiply the dispersion by 0000.1

Kram1032 · Post by **Kram1032** » Fri Feb 15, 2008 2:41 am

OH!
My fault

sry^^
*editing*

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